In the right triangle shown, AC = AC and
BC = BC. What is AB?
We want to find c; let a = BC and b = AC.
So c^2 = BC^2 + AC^2 = AB2.
Then, c = \sqrt{AB2}.
Simplifying the radical gives c = formattedSquareRootOf(AB2).
In the right triangle shown, bside = AC and
AB = AB. What is aside?
We want to find a; let b = AC and c = AB.
So a^2 = c^2 - b^2 = AB^2 - AC^2 = BC2.
Then, a = \sqrt{BC2}.
Simplifying the radical gives a = formattedSquareRootOf(BC2).
We know a^2 + b^2 = c^2.